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Question

The volume of gas A is twice than of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressure of the gases for equal number of moles are

A
pA=2pB
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B
2pA=3pB
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C
pA=3pB
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D
3pA=2pB
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Solution

The correct option is B 2pA=3pB
Given, ZA=3ZB (i)
Compressibility factor (Z) = pVnRT(for real gases)
On substituting in equation (i), we get
pAVAnARTA=3pBVBnBRTB (ii)
Also, it is given that
VA=2VB, nA=nB and TA=TB
Eq. (ii) becomes
pA×2VBnARTB=3pBVBnBRTB
2PA=3PB

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