Question

The volume of gases evolved at $STP$ by passing $0.1A$ of current for $965g$, through an aqueous solution of potassium acetate:

• A. $22.4mL$
• B. $11.2mL$
• C. $89.6mL$
• D. $44.8mL$

Answer 1

Answer: (D)

$44.8mL$

$C{H}_{3}COOK\to C{H}_{3}O{O}^{\ominus }+K^{\oplus }$

At athode, $H_{2}O$ undergoes reduction of give $H_2$.

$2F$ $\equiv$ 1 mol of $H_2$

$2F$ $\equiv$ 1 mol of $C_2{H}_6$ and 2 mol $C{O}_2$

Total volume at cathode and anode = 4 mol = $4\times 22.4$ L

$2F=2\times 96500C\Rightarrow 4\times 22.4L$

$0.1\times 965C\Rightarrow \frac{4\times 22.4\times 0.1\times 965}{2\times 96500}$

$\Rightarrow$ $0.0448L$ = $44.8mL$