Question

The volume of given mass of a gas is 0.6 $d{m}^3$ at a pressure of 101.325K Pa. Calculate the volume of the gas if its pressure is increased to 142.860KPa at the same temperature.

Answer 1

Given,

Initial volume $=V_1=0.6d{m}^3$

Initial pressure $=P_1=101.325kPa$

Final pressure $P_2=142.860kPa$

Temperature is constant

We have to find $V_2$

At constant temperature by Boyle's law,

$P_1{V}_1=P_2{V}_2$
$⟹V_2=\frac{P_1{V}_1}{P_2}$

On substituting values we get,

$V_2=0.426d{m}^3$