Question

The volume of $H_{2}S$ gas measured at $1$ atm and $0^{o}C$ produced when $16.6g$ of $KI$ reacts with excess of $H_2{SO}_4$, is:

• A. $28.00ml$
• B. $280ml$
• C. $80.20ml$
• D. $20.80ml$

Answer 1

The correct option is B $280ml$

According to the reaction,
$8KI+5H_2{SO}_4⟶4K_2{SO}_4+4I_2+H_{2}S+4H_{2}O$

$\because$ $8\times 166g$ of $KI$ gives $22.4L$ of $H_{2}S$

$\therefore$ $16.6g$ of $KI$ will give:

$=\frac{22.4\times 16.6}{8\times 166}=0.280=280ml$

Hence, option B is correct.