The volume of metal in a hollow sphere is constant.If the inner radius is increasing at the rate of 1cm/sec, then the rate of increase of the outer radius when the radii are 4cm and 8cmrespectively is.
A
0.75cm/sec
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B
0.25cm/sec
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C
1cm/sec
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D
0.50cm/sec
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Solution
The correct option is B0.25cm/sec V=43πR3−43πr3 volume is constant. ⇒dVdt=0 ⇒4πR2dRdt−4πr2drdt=0 ⇒64dRdt−16(1)=0 ∴dRdt=0.25cm/sec Hence, option B.