The volume of metallic cylindrical pipe is $748 {c m}^{3}$ . Its length is $14 c m$ and its external radius is $9 c m$ . Find its thickness.

1 c m

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2 c m

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4 c m

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3 c m

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Solution

The correct option is A $1 c m$
Let the radius of cylindrical pipe be ' $r$ ' cm.
external radius $= 9 c m = r_{2}$
length of cylinder $= 148 {c m}^{3} π ({r_{2}}^{2} - {r_{1}}^{2}) \times h = 748 (9^{2} - {r_{1}}^{2}) = \frac{748 \times 7}{14 \times 22} = 17 81 - {r_{1}}^{2} = 17 {r_{1}}^{2} = 81 - 17 = 64 r_{1} = 8 c m$
therefore, thickness of pipe $= r_{2} - r_{1} = 9 - 8 = 1 c m$

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