The volume of one mole of water at 277 K is 18 ml . one contains 20 drops . the number of molecule in one drop of water will be?

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Solution

Dear Navya
$A s s u m e d e n s i t y o f w a t e r a s z e r o . M a s s o f w a t e r = V o l u m e o f w a t e r \times d e n s i t y = 18 \times 1 = 18 g N o o f d r o p s = 18 \times 20 = 360 d r o p s M o l e s o f w a t e r = \frac{m a s s o f w a t e r i n g}{m o l a r m a s s} = \frac{18}{18} = 1 1 m o l e o f a n y s u b s \tan c e c o n t a i n A v o g a d r o n u m b e r o f m o l e c u l e s = 6.022 \times 10^{23} S o 1 d r o p c o n t a i n s = \frac{6.022 \times 10^{23}}{360} = 0.0167 \times 10^{23} = 1.67 \times 10^{21} m o l e c u l e s$

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