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Laws of Chemical Combination

The volume of...

Question

The volume of oxygen evolved at STP, by decomposition of $0.68 g^{'} 20 v o l u m e^{'}$ hydrogen peroxide solution, is:

A

2.24 m L

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B

22.4 m L

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C

224 m L

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D

2240 m L

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Solution

The correct option is C $224 m L$
$\begin{matrix} At STP 68 g H_{2} O_{2} produced O_{2} = 22400 m l At STP 0.68 g H_{2} O_{2} will produce O_{2} = \frac{22400 \times 0.68}{68} = 224 m L \end{matrix}$

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