The volume of oxygen gas at STP required for the complete combustion of 200 mL of acetylene gas at STP (1 atm, 273 K) is:

400 mL

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300 mL

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500 mL

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200 mL

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Solution

The correct option is C 500 mL
The reaction is represented as:
$2 C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$
2 moles of acetylene requires 5 moles of oxygen
$\Rightarrow 2 \times 22400$ mL of acetylene requires $5 \times 22400$ mL of oxygen at STP
volume of oxygen required for 200 mL of acetylene at STP =
$\frac{5 \times 22400}{2 \times 22400} \times 200 = 500$ mL

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What volume of oxygen at STP is required to effect complete combustion of 200cm³ of acetylene and what would be the volume of carbon dioxide formed?

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The volume of oxygen gas at STP required for the complete combustion of 200 mL of acetylene gas at STP (1 atm, 273 K) is:

The correct option is C 500 mLThe reaction is represented as: 2C2H2+5O2→4CO2+2H2O 2 moles of acetylene requires 5 moles of oxygen ⇒2×22400 mL of acetylene requires 5×22400 mL of oxygen at STP volume of oxygen required for 200 mL of acetylene at STP = 5×224002×22400×200=500 mL