Question

The volume of oxygen required for complete oxidation of $2.0$ litres methane at $NTP$ is:

• A. $12.25$ litres
• B. $4$ litres
• C. $1$ litre
• D. $3$ litres

Answer 1

The correct option is B $4$ litres

On complete oxidation of $1mole$ of methane, $2$ $moles$ of $O_2$ is consumed.

$C{H}_4+2O_2⟶C{O}_2+2H_{2}O$

For $1$ $L$ of $C{H}_4⟶2$ $L$ of $O_2$ is needed

$2$ $L$ of $C{H}_4\Rightarrow \left(x\right)$ of $O_2$

$⟹x=\frac{2\times 2}{1}=4$ $L$ of $O_2$

So, for oxidation of $2$ $L$ of $C{H}_4,$ $4$ $L$ of $O_2$ is needed.

Hence, the correct option is $\text{B}$