Question

The volume of oxygen required for complete oxidation of 2 litre of methane at NTP is:

• A. $12.25L$
• B. $4L$
• C. $1L$
• D. $3L$

Answer 1

Answer: (B)

$4L$

Oxidation reaction of methane is as follows:

$C{H}_4+2O_2\to C{O}_2+2H_{2}O$

At same temp. and pressure volume is proportional to moles

So, $1$ mole of $C{H}_4$ requires $2$ moles of $O_2$

Similarly, $2$ liters of $C{H}_4$ at NTP will require $=\frac{2\times 2}{1}=4litersof{O}_2$

Hence, option $B$ is correct.