The volume of the cone in the image is $\frac{2}{3}^{r d}$ of that of the cylinder. The pink portion, which is $\frac{1}{6}^{t h}$ of the total height of the solid, is cut and removed. What is the ratio of the volume of cone to the remaining portion of the cylinder left in the whole solid?

2:3

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3:5

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4:3

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3:1

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Solution

The correct option is C 4:3

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Two solid cones A and B are placed in a cylindrical tube such that their points touch each other inside the tube. The height of the cylinder is 21 cm, and the base diameter is 6cm. The ratio of their capacities is 2:1. Find the heights and capacities of the cones. Also find the volume of the remaining portion of the cylinder.

Two solid cones A and B are placed in a cylindrical tube as shown in the figure below. The ratio of their capacities is 2:1. Find the volume of the remaining portion of the cylinder.

Q. From a right circular cylinder of radius

10

cm and height

21

cm a right circular cone of same base radius is removed. If the volume of the remaining portion is

4400 {cm}^{3}

, then the height of the cone removed is

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The volume of the cone in the image is 23 rd of that of the cylinder. The pink portion, which is 16 th of the total height of the solid, is cut and removed. What is the ratio of the volume of cone to the remaining portion of the cylinder left in the whole solid?

The correct option is C 4:3

The volume of the cone in the image is $\frac{2}{3}^{r d}$ of that of the cylinder. The pink portion, which is $\frac{1}{6}^{t h}$ of the total height of the solid, is cut and removed. What is the ratio of the volume of cone to the remaining portion of the cylinder left in the whole solid?