The volume of the reaction vessel containing an equilibrium mixture is increased in the following reation.
$S O_{2} C l_{2 (g)} ⇌ S O_{2 (g)} + C l_{2 (g)}$ .
When equilibrium is re-established :

the amount of

C l_{2 (g)}

remains unchanged

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the amount

C l_{2 (g)}

increases

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

the amount of

S O_{2} C l_{2 (g)}

increases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the amount of

S O_{2 (g)}

drcreases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A the amount $C l_{2 (g)}$ increases
$S O_{2} {C l}_{2 (g)} ⇌ S O_{2 (g)} + {C l}_{2 (g)}$
When the volume of the vessel increases pressure decreases. Hence according to Le-Chatlier principle the equilibrium shift in a direction to increase the presure i.e., towards right as more gas molecules are produced.
So, the amount of ${C l}_{2 (g)}$ increases.

Suggest Corrections

Similar questions

S O_{2} C l_{2} (g) ⇋ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

Join BYJU'S Learning Program