the volume of two vessels are 5 liters and 3 liters respectively. Air is filled in them at pressure of 3 atmos and 5 atmos respectively. At constant temperature if they are connected through a tube the resultant pressure will be-

3.5 atmos

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3.75 atmos

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4 atmos

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4.25 atmos

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Solution

The correct option is B 3.75 atmos
Let $P$ be the final pressure of the mixture.

Then,

$P (V_{1} + V_{2}) = P_{1} V_{1} + P_{2} V_{2}$

$P \times 8 = 5 \times 3 + 3 \times 5$

$P = \frac{30}{8} = 3.75$ atmosphere

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the volume of two vessels are 5 liters and 3 liters respectively. Air is filled in them at pressure of 3 atmos and 5 atmos respectively. At constant temperature if they are connected through a tube the resultant pressure will be-

The correct option is B 3.75 atmosLet P be the final pressure of the mixture.Then,P(V1+V2)=P1V1+P2V2P×8=5×3+3×5P=308=3.75 atmosphere

The correct option is B 3.75 atmos
Let $P$ be the final pressure of the mixture.

Then,

$P (V_{1} + V_{2}) = P_{1} V_{1} + P_{2} V_{2}$

$P \times 8 = 5 \times 3 + 3 \times 5$

$P = \frac{30}{8} = 3.75$ atmosphere