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Question

The volume of water to be added to 100 cm3 of 0.5 N H2SO4 to get decinormal concentration is:

A
100 cm3
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B
450 cm3
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C
500 cm3
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D
400 cm3
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Solution

The correct option is D 400 cm3
N1V1=N2V2

Given,
N1=0.5 N,
N2=0.1 N,
V1=100 cm3,
V2=?

0.5×100=0.1×V2
V2=500 cm3 (Total final volume)


Volume to be added
=500100=400 cm3.

Hence, the correct option is D

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