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Question

The volume of water to be added to 100 cm3 of 0.5N H2SO4 to get decinormal concentration is


A

100 cm3

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B

450 cm3

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C

500 cm3

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D

400 cm3

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Solution

The correct option is D

400 cm3


Let the total volume of solution = x

V2=N1 V1N2=0.5×1000.1=500cm3

The volume of water added = 500 – 100

400 cm3


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