The volume of water to be added to 100 cm3 of 0.5N H2SO4 to get decinormal concentration is
100 cm3
450 cm3
500 cm3
400 cm3
Let the total volume of solution = x
∴ V2=N1 V1N2=0.5×1000.1=500cm3
∴ The volume of water added = 500 – 100