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Question

The volume of water to be added to 100 cm3 of a 0.5 N H2SO4 to get a decinormal solution is:

A
200 cm3
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B
300 cm3
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C
400 cm3
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D
500 cm3
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Solution

The correct option is C 400 cm3
As per the concept of dilution,
N1V1=N2V2
Decinormal means that the normality =0.1 N
(0.5×100)=(0.1×V2)
V2=500 cm3
So, the volume of water added should be (500100) cm3=400 cm3

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