Question

The volume of water to be added to $400mL$ of $N/8HCl$ to make it exactly $N/12$, is

• A. $400mL$
• B. $300mL$
• C. $200mL$
• D. $100mL$

Answer 1

Answer: (C)

$200mL$

$N_1$ is normality of $HCl$ before adding water and $V_1$ is volume.

$N_{1}and{V}_1$ are normality and volume after adding water.

Applying formula,

$N_1{V}_1=N_2{V}_2$

$\therefore \frac{1}{8}\times 400=\frac{1}{12}\times V_2$

$\therefore V_2=50\times 12$ml

V$=600ml-400ml=200$ml

Hence, option C is correct.