Question

The volume of water to be added to 500 ml of 0.25 N hydrochloric acid to make it exactly decinormal is:

• A. 500 ml
• B. 750 ml
• C. 250 ml
• D. 200 ml

Answer 1

The correct option is B 750 ml

The number of equivalents is the same.

$N_1{V}_1=N_2{V}_2$

$N_1=0.25N$

$V_1=500ml$

$N_2=\frac{1}{10}$ (decinormal)

$0.25\times 500=0.1\times V_2$

$V_2=1250ml$

The volume of water added $=1250-500$

$=750ml$