Question

The volume of water to be added to $\frac{N}{2}$ HCl to prepare $500c{m}^3$ of $\frac{N}{10}$ solution is :

• A. $450c{m}^3$
• B. $100c{m}^3$
• C. $45c{m}^3$
• D. $400c{m}^3$

Answer 1

The correct option is D $400c{m}^3$

Let $Vc{m}^3$ be the volume of water required to $\frac{N}{2}$ HCl to prepare $500c{m}^3$ of $\frac{N}{10}$ solution.

$NV=N^{\prime }{V}^{\prime }$

$\frac{1}{2}\times V=\frac{1}{10}\times 500$

$V=100c{m}^3$.

So the volume of water added $=500-100=400c{m}^3$

Hence, option D is correct.