The volume required to prepare 2.0L of 3.0MH2SO4 solution from 96%( w/w)H2SO4 solution (density =2gmL−1) is
A
242.85 mL
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B
306.25 mL
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C
385.20mL
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D
450.10 mL
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Solution
The correct option is B306.25 mL Moles of HCl in 2.0L of 3.0M solution =(2.0L)×(3.0mol L−1)=6.0mol
Mass of H2SO4 in this solution =(6.0mol)×(98 g mol−1)=588g
Mass of 96%H2SO4 solution containing 588 g of H2SO4 =588×100g96=612.5 g
Volume of 96%H2SO4 solution weighing 612.5g =612.5g2g~mL−1=306.25mL