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Question

The volume required to prepare 2.0 L of 3.0 M H2SO4 solution from 96% ( w/w) H2SO4 solution (density =2 g mL1) is

A
242.85 mL
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B
306.25 mL
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C
385.20 mL
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D
450.10 mL
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Solution

The correct option is B 306.25 mL
Moles of HCl in 2.0 L of 3.0 M solution
=(2.0 L)×(3.0 mol L1)=6.0 mol
Mass of H2SO4 in this solution =(6.0 mol)×(98 g mol1)=588 g
Mass of 96% H2SO4 solution containing 588 g of H2SO4
=588×100 g96=612.5 g
Volume of 96% H2SO4 solution weighing 612.5 g
=612.5 g2 g~mL1=306.25 mL

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