The volume strength of $1$ M $H_{2} O_{2}$ is:

[Molar mass of $H_{2} O_{2} = 34$ g $m o l^{- 1}$ ]

16.8

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11.2

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22.4

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5.6

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Solution

The correct option is B $11.2$
$1 L - 1 M H_{2} O_{2}$ solution will produce $11.2 L$ of $O_{2}$ gas at STP.
Since, Molarity $= \frac{Volume strength}{11.2}$

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