The volume-temperature graphs of a given mass of an ideal gas at constant pressure are shown below:
What is the correct order of pressures?

p_{1} > p_{3} > p_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

p_{1} > p_{2} > p_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p_{2} > p_{3} > p_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p_{2} > p_{1} > p_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $p_{1} > p_{3} > p_{2}$
Ideal gas equation, $P V = n R T$

At constant $P$ , $V = k T$

So graph will be a straight line with slope $k = n R / P$
Higher the slope lower will be the pressure.

Correct order of pressure $p_{1} > p_{3} > p_{2}$ as order of slope is
$p_{2} > p_{3} > p_{1}$ .

Suggest Corrections

Similar questions

A plot of volume (V) versus temperature (T) for a gas at constant pressure is a straight line passing through the origin. The plots at different values of pressure are shown in figure. Which of the following order of pressure is correct for this gas?