Question

The volume(V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is?

• A. $\frac{1}{3}$
• B. $\frac{2}{5}$
• C. $\frac{2}{7}$
• D. $\frac{2}{3}$

Answer 1

The correct option is B $\frac{2}{5}$

$\frac{workdone}{heatabsorbed}=\frac{n{C}_p\Delta T-n{C}_v\Delta T}{n{C}_p\Delta T}=1-\frac{1}{\gamma }=\frac{2}{5}$