The volume (V) versus temperature (T) graph of an ideal gas of given mass, undergoing a thermodynamic process is shown below. During this process, if the temperature increases, then the pressure of the gas
A
first increases then decreases
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
continuously decreases
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
continuously increases
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
first decreases then increases
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B continuously decreases By Extrapolating the given graph we get, V=mT−c..........(1)
Here, m is the slope of straight line and c is the negative y− intercept.
From the ideal gas equation, PV=nRT
we can write that, P=nRTV ⇒P=nRTmT−c [from (1)] ⇒P=nRm−cT
From this, we can see that, as T increases, cT decreases, (m−cT) increases, hence, P decreases.
Therefore, pressure decreases continuously as temperature increases continuously in the given thermodynamic process.
Thus, option (b) is the correct answer.