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Standard XII

Physics

1st Law of Thermodynamics

The volume ...

Question

The volume $V$ versus temperature $T$ graphs for a certain amount of a perfect gas at two pressures $p_{1}$ and $p_{2}$ are as shown in Fig. It follows from the graphs that $p_{1}$ is greater than $p_{2}$ .

True

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False

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Solution

The correct option is A True
$\frac{P V}{T} = c o n s t a n t$
For a particular temperature $T_{1}$
We have $p \propto \frac{1}{V}$
Since, $V_{1} > V_{2}, p_{2} < p_{1}$
$\Rightarrow p_{1} > p_{2}$ .

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The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressures p1 and p2 are as shown in Fig. It follows from the graphs that p1 is greater than p2.

The correct option is A TruePVT=constantFor a particular temperature T1We have p∝1VSince, V1>V2,p2<p1⇒p1>p2.

The volume $V$ versus temperature $T$ graphs for a certain amount of a perfect gas at two pressures $p_{1}$ and $p_{2}$ are as shown in Fig. It follows from the graphs that $p_{1}$ is greater than $p_{2}$ .

The correct option is A True
$\frac{P V}{T} = c o n s t a n t$
For a particular temperature $T_{1}$
We have $p \propto \frac{1}{V}$
Since, $V_{1} > V_{2}, p_{2} < p_{1}$
$\Rightarrow p_{1} > p_{2}$ .