Question

The volume vs. temperature graph of 1 mole of an ideal gas is given below.

The pressure of the gas (in atm) at $X,Y$ and $Z$, respectively, are:

• A. $0.328,0.820,0.820$
• B. $3.28,8.20,3.28$
• C. $0.238,0.280,0.280$
• D. $32.8,0.280,82.0$

Answer 1

The correct option is A $0.328,0.820,0.820$

Using ideal gas equation, $PV=nRT$

For gas $X$,

$p=\frac{nRT}{V};P=\frac{1\times 0.082\times 200}{50}=0.32atm$

For gas $Y$,

$P=\frac{1\times 0.082\times 500}{50}=0.820atm$

For gas $Z$,

$P=\frac{1\times 0.082\times 200}{20}=0.820atm$

Hence, option $A$ is correct.