Question

The volume was changed while temperature held constant until the pressure was 1.6 atm. Which is equal to the new volume?

• A. $\frac{5.0\times 1.5}{1.6}$
• B. $\frac{5.0\times 1.6}{1.5}$
• C. $\frac{25\times 1.5}{1.6}$
• D. $\frac{0.08\times 1.6}{1.5}$
• E. $\frac{0.08\times 1.5}{1.6}$

Answer 1

The correct option is A $\frac{5.0\times 1.5}{1.6}$

Using ideal gas equation at costant temperature

$P_1{V}_1$$=$$P_2{V}_2$

$1.5\times 5$$=$$1.6\times V_2$

or, $V_2$$=$$1.5\times 5/1.6$$=$$4.7L$