The wall is $21$ m high. Rushkil wants to climb the wall with the help of a ladder whose base is to be placed $20$ m away from the base of the wall. What is the required minimum length of the ladder such that Rushkil can climb the wall easily?

25

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29

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21

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Solution

The correct option is C $29$ m
The position of the ladder with respect to the wall is shown below:

The above situation can be shown as,

Now, let the length of ladder be $x$ .

Applying Pythagoras theorem,
$x^{2} = 21^{2} + 20^{2}$
$x = \sqrt{441 + 400}$
$x = \sqrt{841}$
(using the given options)
$x = 29$ m
Hence, minimum $29$ m of ladder will be required.
So, option $(c)$ correct.

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The wall is 21 m high. Rushkil wants to climb the wall with the help of a ladder whose base is to be placed 20 m away from the base of the wall. What is the required minimum length of the ladder such that Rushkil can climb the wall easily?

The wall is $21$ m high. Rushkil wants to climb the wall with the help of a ladder whose base is to be placed $20$ m away from the base of the wall. What is the required minimum length of the ladder such that Rushkil can climb the wall easily?