The walls and ceiling of a room are to be plastered. The length, breadth and height of the room are 4.5 m, 3 m and 350 cm, respectively. Find the cost of plastering at the rate of Rs 8 per square metre.

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Solution

$Length of a room = 4.5 m Breadth = 3 m Height = 350 cm = \frac{350}{100} m (∵ 1 m = 100 cm) = 3.5 m Since only the walls and the ceiling of the room are to be plastered, we have : So, total area to be plastered = area of the ceiling + area of the walls = (length \times breadth) + 2 \times (length \times height + breadth \times height) = (4.5 \times 3) + 2 \times (4.5 \times 3.5 + 3 \times 3.5) = 13.5 + 2 \times (15.75 + 10.5) = 13.5 + 2 \times (26.25) = 66 m^{2} Again, cost of plastering an area of 1 m^{2} = Rs 8 ∴ Total cost of plastering an area of 66 m^{2} = 66 \times 8 = Rs 528$

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The walls and ceiling of a room are to be plastered. The length, breadth and height of the room are 4.5 m, 3 m and 350 cm respectively. Find the cost of plastering at the rate of Rs. 8 per $m^{2}$ .

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