The water content of a saturated soil and specific gravity of soil solids were found to be 30% and 2.70 respectively. Assuming the unit wt of water to be $10 k N / m^{3}$ , the saturated unit wt (kN/ $m^{3}$ ) and the void ratio of the soil are

19.4, 0.81

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18.5, 0.30

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19.4, 0.45

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18.5, 0.45

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Solution

The correct option is A 19.4, 0.81
Soil is saturated, so S = 1

Water content, w = 30 %

$S p e c i f i c g r a v i t y, G_{s} = 2.7$

$U n i t w e i g h t o f w a t e r, γ_{w} = 10 k N / m^{3}$

$W e k n o w, S e = w G_{s}$

$\Rightarrow e = \frac{0.3 \times 2.7}{1} = 0.81$

$γ_{s a t} = (\frac{2.7 + 0.81}{1 + 0.81}) \times 10$

$= 19.39 k N / m^{3}$

$= 19.4 k N / m^{3}$

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The water content of a saturated soil and specific gravity of soil solids were found to be 30% and 2.70 respectively. Assuming the unit wt of water to be 10 kN/m3, the saturated unit wt (kN/m3) and the void ratio of the soil are

The correct option is A 19.4, 0.81Soil is saturated, so S = 1 Water content, w = 30 % Specific gravity,Gs=2.7 Unit weight of water, γw=10 kN/m3 We know, Se=wGs ⇒e=0.3×2.71=0.81 γsat=(2.7+0.811+0.81)×10 =19.39 kN/m3 =19.4 kN/m3

The water content of a saturated soil and specific gravity of soil solids were found to be 30% and 2.70 respectively. Assuming the unit wt of water to be $10 k N / m^{3}$ , the saturated unit wt (kN/ $m^{3}$ ) and the void ratio of the soil are