The water drops fall at regular intervals from a tap 5m above the ground. The third drop is leaving the tap at the instant the first drop touches the ground. How far above the ground is the second drop at the instant?
Time for download journey t=√2hg=√2×510=1s
So far regular interval drops are falling at interval of 1/2 sec
distance fallen by 2nd drop =12g(12)2=54m
height of 2nd drop =5−54=154=3.75m