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Question

# The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant?

A
1.25 m
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B
2.50 m
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C
3.75 m
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D
4.00 m
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Solution

## The correct option is C 3.75 mHeight of tap = 5m and (g) = 10m/sec2For the first drop, 5=ut+gt2=(0×t)+×10t2v=5t2 or t2=1 or t=1.It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.Distance covered by the second drop in 0.5 sec.=(0.5)2=1.25mTherefore, distance of the second drop above the ground=5−1.25=3.75m

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