Question

The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant?

• A. 1.25 m
• B. 2.50 m
• C. 3.75 m
• D. 4.00 m

Answer 1

The correct option is C 3.75 m

Height of tap = 5m and (g) = $10m/se{c}^2$

For the first drop, $5=ut+g{t}^2$

$=(0\times t)+\times 10t^{2v}=5t^2$ or $t^2=1$ or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

$=(0.5{)}^2=1.25m$

Therefore, distance of the second drop above the ground

$=5-1.25=3.75m$