The water equivalent of a copper calorimeter is 4.5g. If the specific heat of copper is 0.09cal g−1C−1, then
A
Mass of the calorimeter is 0.5kg.
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B
Thermal capacity of the calorimeter is 4.5cal∘C−1.
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C
Heat required to raise the temperature of the calorimeter by 8∘C will be 36cal
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D
Heat required to melt 15gm of ice placed in the calorimeter will be 1200cal
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Solution
The correct options are B Thermal capacity of the calorimeter is 4.5cal∘C−1. C Heat required to raise the temperature of the calorimeter by 8∘C will be 36cal D Heat required to melt 15gm of ice placed in the calorimeter will be 1200cal W=(msSω)⇒4.5=m×0.091 ∴m=4.50.09=50g=0.05kg (b) Thermal capacity = ms =4.5×1cal∘C−1=4.5cal∘C−1 (c)Q=msΔT=4.5×8cal=36cal (d)Q=mL=15×80=1200cal
Why this question?
Basic definition of water equivalent and thermal capacity. JEE asks questions on these basic definitions.