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Question

The water equivalent of a copper calorimeter is 4.5 g. If the specific heat of copper is 0.09 cal g1C1, then

A
Mass of the calorimeter is 0.5 kg.
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B
Thermal capacity of the calorimeter is 4.5 calC1.
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C
Heat required to raise the temperature of the calorimeter by 8C will be 36 cal
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D
Heat required to melt 15 gm of ice placed in the calorimeter will be 1200 cal
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Solution

The correct option is D Heat required to melt 15 gm of ice placed in the calorimeter will be 1200 cal
W=(msSω)4.5=m×0.091
m=4.50.09=50 g=0.05 kg
(b) Thermal capacity = ms
=4.5×1 calC1=4.5 calC1
(c)Q=msΔT=4.5×8 cal=36 cal
(d)Q=mL=15×80=1200 cal
Why this question?

Key concept: Basic definition of water equivalent and thermal capacity.

Importance in JEE: Questions related to basic concepts are common in JEE.

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