The water of volume 4 m3 at the height 20 m is pressed by 2- 105N pressure- The work done by motor is

The correct option is B 16× 10^5J Work W = mgh + pV = Vρ gh + pV = 4× 10^3× 10× 20 + (2× 10^5)× 4 = 16× 10^5J . ...

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Standard XII

Physics

Average and Instaneous Power

The water of ...

Question

The water of volume $4 m^{3}$ at the height $20 m$ is pressed by $2 \times 10^{5} N$ pressure. The work done by motor is

8 \times 10^{5} J

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16 \times 10^{5} J

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12 \times 10^{5} J

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32 \times 10^{5} J

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Solution

The correct option is B $16 \times 10^{5} J$
Work $W = m g h + △ p V$
$= V ρ g h + △ p V$
$= 4 \times 10^{3} \times 10 \times 20 + (2 \times 10^{5}) \times 4$
$= 16 \times 10^{5} J$ .

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The water of volume 4 m3 at the height 20 m is pressed by 2×105N pressure. The work done by motor is

The correct option is B 16×105JWork W=mgh+△pV=Vρgh+△pV=4×103×10×20+(2×105)×4=16×105J.

The water of volume $4 m^{3}$ at the height $20 m$ is pressed by $2 \times 10^{5} N$ pressure. The work done by motor is

The correct option is B $16 \times 10^{5} J$
Work $W = m g h + △ p V$
$= V ρ g h + △ p V$
$= 4 \times 10^{3} \times 10 \times 20 + (2 \times 10^{5}) \times 4$
$= 16 \times 10^{5} J$ .