The water potential of pure water is zero. If it is converted into a solution of 0.1 M concentration, the water potential
A
Remains unchanged
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B
Is decreased by 0.1%
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C
And solute potential is increased by 2.3 bars
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D
Decreases by 2.3 bars
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Solution
The correct option is D Decreases by 2.3 bars Water potential of pure water at normal pressure and temperature is zero. Water potential is equal to the solute potential of the solution. Water potential is calculated by the formula, water potential = -iCRT
Where i = ionization constant
C = Molar concentration
R = Pressure constant = 0.0831 liter bar/mole K
T = Temperature in degrees Kelvin = 273 oC
Thus, water potential of 0.1 M solution is -1 x 0.1 x 0.0831 x 273 = -2.3 bars.