The wave function - of 2s is given by - 2s - 1 2- 2- 1 a 0 1 - 2 2- r a 0 e -r - 2 a 0At r- r 0- radial node is formed- Thus for 2s- r 0 in terms of a 0 is-

The correct option is B r _ 0 =2 a _ 0 When r= r _ 0 , Ψ #160;_ 2s =0 , then from the given equation: #160; #160; #160; #160; #1 ...

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Byju's Answer

Standard XII

Chemistry

Schrodinger Equation

The wave func...

Question

The wave function $(Ψ)$ of $2 s$ is given by
$Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{1 / 2} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}$
At $r = r_{0}$ , radial node is formed. Thus for $2 s$ , $r_{0}$ in terms of $a_{0}$ is:

r_{0} = a_{0}

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r_{0} = 2 a_{0}

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r_{0} = a_{0} / 2

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r_{0} = 4 a_{0}

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Solution

The correct option is B $r_{0} = 2 a_{0}$
When $r = r_{0}$ , $Ψ_{2 s} = 0$ , then from the given equation:
$2 - \frac{r}{a_{0}} = 0$
$r = 2 a_{0}$ .

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Similar questions

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}

r = r_{0}

radial node is formed. Thus for

2 s

r_{0}

in terms of

a_{0}

is:

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- \frac{r}{2 a_{0}}}

r = r_{0}

, radial node is formed. Thus for

2 s

r_{0}

in terms of

a_{0}

is:

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{(- r / a_{0})}

Where

a_{0}

is Bohr's radius. If the radial node in

2 s

is at

r_{0},

then find

r_{0}

in terms of

a_{0}

Q. The wave function

(ψ)

2 s

-orbitals given by:

ψ_{2 s} = \frac{1}{\sqrt{32 π}} {[\frac{1}{a_{0}}]}^{3 / 2} [2 - \frac{r}{a_{0}}] e^{- r / 2 a_{0}}

r = r_{0}

,radial node is formed.If

r_{0}

x a_{0}

, find the value of

x

Q. The wave function

(Ψ)

2 s

is given by:

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{(- r / a_{0})}

Where

a_{0}

is Bohr's radius. If the radial node in

2 s

is at

r_{0},

then find

r_{0}

in terms of

a_{0}

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The wave function (Ψ) of 2s is given by Ψ2s=12√2π(1a0)1/2{2−ra0}e−r/2a0At r=r0, radial node is formed. Thus for 2s, r0 in terms of a0 is:

The correct option is B r0=2a0When r=r0, Ψ2s=0, then from the given equation: 2−ra0=0 r=2a0.

The wave function $(Ψ)$ of $2 s$ is given by
$Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{1 / 2} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}$
At $r = r_{0}$ , radial node is formed. Thus for $2 s$ , $r_{0}$ in terms of $a_{0}$ is:

The correct option is B $r_{0} = 2 a_{0}$
When $r = r_{0}$ , $Ψ_{2 s} = 0$ , then from the given equation:
$2 - \frac{r}{a_{0}} = 0$
$r = 2 a_{0}$ .