The wave function of 2s electrons is given by - - 2s- 14-2- 1a0 3-2 2-ra0 e 2-r-a0 If it has a node at r - r0- then the relation between r0 and a0 is-

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The wave func...

Question

The wave function of 2s electrons is given by : $Ψ_{2 s} = \frac{1}{4 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{3 / 2} (2 - \frac{r}{a^{0}}) e^{(2 - \frac{r}{a_{0}})}$
If it has a node at $r = r_{0}$ , then the relation between $r_{0}$ and $a_{0}$ is:

r_{0} = 2 a_{0}

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r_{0} > 2 a_{0}

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r_{0} < 2 a_{0}

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none of the above

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Solution

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Similar questions

(Ψ)

2 s

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{1 / 2} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}

r = r_{0}

2 s

r_{0}

a_{0}

(ψ)

2 s

ψ_{2 s} = \frac{1}{\sqrt{32 π}} {[\frac{1}{a_{0}}]}^{3 / 2} [2 - \frac{r}{a_{0}}] e^{- r / 2 a_{0}}

r = r_{0}

r_{0}

x a_{0}

x

2 s

Ψ (2 s) = \frac{1}{4 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{3 / 2} (2 - \frac{r}{a_{0}}) e^{(2 - \frac{r}{a_{0}})}

r = r_{0}

r_{0}

a_{0}

(Ψ)

2 s

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- r / 2 a_{0}}

r = r_{0}

2 s

r_{0}

a_{0}

(Ψ)

2 s

Ψ_{2 s} = \frac{1}{2 \sqrt{2 π}} {(\frac{1}{a_{0}})}^{\frac{1}{2}} {2 - \frac{r}{a_{0}}} e^{- \frac{r}{2 a_{0}}}

r = r_{0}

2 s

r_{0}

a_{0}

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