The wave function (Ψ) of 2s is given by: Ψ2s=12√2π(1a0)12{2−ra0}e(−r/a0) Where a0 is Bohr's radius. If the radial node in 2s is at r0, then find r0 in terms of a0.
A
a0
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B
2a0
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C
3−(5)12a0
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D
None of these
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Solution
The correct option is B2a0 ψ22s= Probability density of finding electron ψ22s=0 (at node) (∵ probability of finding an electron is zero at the node) ∴0=18π(1a0)(2−r0a0)2e(−2r0a0) (squaring the given value of ψ2s) or [2−r0a0]=0;∴2=r0a0;2a0=r0