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Byju's Answer
Standard XII
Chemistry
Shapes of Orbitals and Nodes
The wave func...
Question
The wave function
(
ψ
)
of
2
s
-orbitals given by:
ψ
2
s
=
1
√
32
π
[
1
a
0
]
3
/
2
[
2
−
r
a
0
]
e
−
r
/
2
a
0
at
r
=
r
0
,radial node is formed.If
r
0
=
x
a
0
, find the value of
x
.
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Solution
ψ
2
s
=
1
√
32
π
[
1
a
0
]
3
/
2
[
2
−
r
a
0
]
e
−
r
/
2
a
0
For radial node at
r
=
r
0
,
ψ
2
2
s
=
0
. This is possible only when
[
2
−
r
0
a
0
]
=
0
∴
r
0
=
2
a
0
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0
Similar questions
Q.
The wave function
(
Ψ
)
of
2
s
is given by
Ψ
2
s
=
1
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√
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π
(
1
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0
)
1
/
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{
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}
e
−
r
/
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0
At
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Q.
The wave function
(
Ψ
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of
2
s
is given by:
Ψ
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=
1
2
√
2
π
(
1
a
0
)
1
2
{
2
−
r
a
0
}
e
−
r
2
a
0
At
r
=
r
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, radial node is formed. Thus for
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s
,
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is:
Q.
The wave function
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Ψ
)
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is given by:
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s
=
1
2
√
2
π
(
1
a
0
)
1
2
{
2
−
r
a
0
}
e
(
−
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/
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0
)
Where
a
0
is Bohr's radius. If the radial node in
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s
is at
r
0
,
then find
r
0
in terms of
a
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Q.
The wave function
(
Ψ
)
of
2
s
is given by:
Ψ
2
s
=
1
2
√
2
π
(
1
a
0
)
1
2
{
2
−
r
a
0
}
e
−
r
/
2
a
0
At
r
=
r
0
radial node is formed. Thus for
2
s
,
r
0
in terms of
a
0
is:
Q.
The wave function of
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Ψ
(
2
s
)
=
1
4
√
2
π
(
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a
0
)
3
/
2
(
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a
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e
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0
and
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0
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