Question

The wave motion has the function $y=a_{0}sin(\omega t-kx)$. The graph in the figure shows how the displacement y at a fixed point varies with time t. Which one of the labelled points shows a displacement equal to that at the position $x=\frac{\pi }{2k}$ at time t = 0?

• A. P
• B. Q
• C. R
• D. S

Answer 1

The correct option is B Q

Given $y=a_{0}sin(\omega t-kx)$
Put t = 0 and $x=\frac{\pi }{2k}$
$y=a_{0}sin(\omega \times 0-\frac{k\pi }{2k})\Rightarrow y=-a_0$
This corresponds to point Q.