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Byju's Answer
Standard XII
Chemistry
Emission and Absorption Spectra
The wave numb...
Question
The wave number of hydrogen atom in Lyman series is
82200
c
m
−
1
. The electron goes from:
A
n
3
→
n
2
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B
n
2
→
n
1
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C
n
4
→
n
3
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D
none of these
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Solution
The correct option is
A
n
2
→
n
1
According to Rydberg formula:
¯
v
=
R
(
1
n
2
1
−
1
n
2
2
)
Here,
R
=
109677
=
109678
c
m
−
1
and
¯
v
=
82200
c
m
−
1
thus,
82200
109678
=
(
1
1
2
−
1
n
2
2
)
or
3
4
=
(
1
−
1
n
2
2
)
or
1
n
2
2
=
1
−
3
4
=
1
4
or
n
2
=
2
.
∴
The electron jumps from second orbit
(
n
2
)
to ground state
(
n
1
)
.
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___
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