Question

The wavelength associated with an electron accelerated through a potential difference of 100 V is nearly

• A. $100\dot{A}$
• B. $123\dot{A}$
• C. $1.23\dot{A}$
• D. $0.123\dot{A}$

Answer 1

The correct option is C

$1.23\dot{A}$

$\lambda =\frac{h}{\sqrt{2mQV}}=\frac{6.6\times {10}^{-34}}{\sqrt{2\times 9.1\times {10}^{-31}\times 1.6\times {10}^{-19}\times 100}}=1.23\dot{A}$