Question

The wavelength front of light wave traveling in vacuum are given by x + y + z = c .The angle made by the ray with the x-axis is :

Answer 1

Given that, $x+y+z=c$

The given equation in the plane equation form, $lx+my+nz=p$

So, $\frac{1}{\sqrt{3}}x+\frac{1}{\sqrt{3}}y+\frac{1}{\sqrt{3}}z=\frac{c}{\sqrt{3}}$

Let $\theta$is the angle between the normal and +x-axis, then

$\cos \theta =\frac{1}{\sqrt{3}}$

$\theta ={\cos }^{-1}\left(\frac{1}{\sqrt{3}}\right)$