The wavelength of a photon is $4000$ $˚ A$ . Calculate its energy:

49.5 \times 10^{- 19}

J

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495 \times 10^{- 19}

J

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4.95 \times 10^{- 19}

k J

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4.95 \times 10^{- 19}

J

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Solution

The correct option is D $4.95 \times 10^{- 19}$ $J$
$λ = 4000 ˚ A = 4000 \times 10^{- 10}$
$E = \frac{h c}{λ}$
$h = 6.6 \times 10^{- 34}$
$E = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{4000 \times 10^{- 10}}$
$E = 4.95 \times 10^{- 19}$ $J$

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The wavelength of a photon is 4000 ˚A. Calculate its energy:

The correct option is D 4.95×10−19 Jλ=4000˚A=4000×10−10E=hcλh=6.6×10−34E=6.6×10−34×3×1084000×10−10E=4.95×10−19 J

The wavelength of a photon is $4000$ $˚ A$ . Calculate its energy:

The correct option is D $4.95 \times 10^{- 19}$ $J$
$λ = 4000 ˚ A = 4000 \times 10^{- 10}$
$E = \frac{h c}{λ}$
$h = 6.6 \times 10^{- 34}$
$E = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{4000 \times 10^{- 10}}$
$E = 4.95 \times 10^{- 19}$ $J$