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Question

The wavelength of electrons accelerated from rest through a potential difference of 40 kV is x×1012m. The value of x is . (Nearest integer)
Given: Mass of electron =9.1×1031 kg
Charge on an electron =1.6×1019 C
Planck's constant =6.63×1034 Js

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Solution

Wavelength (λ)of electron is given by
λ=h2mqV
Here
h is planck's constant
m is mass of electron
q is harge on electron
V is potential difference

Putting the values:
λ=6.63×10342×9.1×1031×1.6×1019×40×103

=6.63×1034116.48×1046=6.144×1012=6×1012

x=6

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