wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

The wavelength of electrons accelerated from rest through a potential difference of 40 kV is x×1012m. The value of x is . (Nearest integer)
Given: Mass of electron =9.1×1031 kg
Charge on an electron =1.6×1019 C
Planck's constant =6.63×1034 Js

Open in App
Solution

Wavelength (λ)of electron is given by
λ=h2mqV
Here
h is planck's constant
m is mass of electron
q is harge on electron
V is potential difference

Putting the values:
λ=6.63×10342×9.1×1031×1.6×1019×40×103

=6.63×1034116.48×1046=6.144×1012=6×1012

x=6

flag
Suggest Corrections
thumbs-up
66
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equipotential Surfaces
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon