Question

The wavelength of emitted $\gamma$ rays are in the other

• A. ${\lambda }_{\gamma 2}>{\lambda }_{\gamma 3}>{\lambda }_{\gamma 1}$
• B. ${\lambda }_{\gamma 3}>{\lambda }_{\gamma 2}>{\lambda }_{\gamma 1}$
• C. ${\lambda }_{\gamma 1}>{\lambda }_{\gamma 2}>{\lambda }_{\gamma 3}$
• D. ${\lambda }_{\gamma 3}>{\lambda }_{\gamma 1}>{\lambda }_{\gamma 2}$

Answer 1

The correct option is A ${\lambda }_{\gamma 2}>{\lambda }_{\gamma 3}>{\lambda }_{\gamma 1}$

As the frequencies of $\gamma -rays$ are in the order:

${\nu }_{\gamma 1}>{\nu }_{\gamma 3}>{\nu }_{\gamma 2}$

Thus as wavelength is inversely proportional to frequency.

${\lambda }_{\gamma 2}>{\lambda }_{\gamma 3}>{\lambda }_{\gamma 1}$

Hence option A is correct