Question

The wavelength of first line of the Lymen series for hydrogen is 1216 $A^{\circ }$. The wavelength for the first line of this series for a 10 time ionised sodium atom (z = 11) will be :

• A. 1000 $A^{\circ }$
• B. 100 $A^{\circ }$
• C. 10 $A^{\circ }$
• D. 1 $A^{\circ }$

Answer 1

The correct option is C 10 $A^{\circ }$

For $N{a}^{+10}$ ; Z = 11
$\frac{1216=\frac{1}{R}\left(\frac{1\times 4}{3}\right)}{x=\frac{1}{R\left(121\right)}\left(\frac{1\times 4}{3}\right)}$
$\frac{1216}{x}=121$
$x=\frac{1216}{121}\Rightarrow x=10A^0$