wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The wavelength of light for the least energetic photon emitted in the Lyman series of the hydrogen atom spectrum is ___ nm

Open in App
Solution

Least energy is the cue my friend.

Energy is hcλ

Least energy means hcλ should be less. hc is constant

So 1λ should be less

By Rydberg’s formula; 1λ=R(1n211n22)

For Lyman, n1=1

1λ=R(111n22)

n2 can be from 2, ….

To minimize 1λ what should be n2

2 right and not α

So Let’s find λ

1λ=R(34)λ=43R=43×1.09×107=1.22×107=122 nm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrogen Spectrum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon