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Question

The wavelength of light for the least energetic photon emitted in the Lyman series of the hydrogen atom spectrum is ___ nm

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Solution

Least energy is the cue my friend.

Energy is hcλ

Least energy means hcλ should be less. hc is constant

So 1λ should be less

By Rydberg’s formula; 1λ=R(1n211n22)

For Lyman, n1=1

1λ=R(111n22)

n2 can be from 2, ….

To minimize 1λ what should be n2

2 right and not α

So Let’s find λ

1λ=R(34)λ=43R=43×1.09×107=1.22×107=122 nm


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